A UI designer wants to layout three components on the diagonal.

Describe the minimum number of layout managers needed to get this design.
A grid manager set up with three rows and columns will do the job. (Grid
Layout, 350 (7th ed.) or 373 (8th ed.))
The answers, in no particular order:
- 3. One for the frame, one for the lines [?], one for the square.
- There will need to be a screen layout manager and three managers for
the components. 4 minimum.
- Three: north + left; center + center; south + right.
- Two, one to create an initial square, and a second to accept
coordinates and a copy of the first manager.
- At the very least, a 3-row grid would be needed as well as 3 JPanels
and the 3 components that are to be displayed, so all that would be needed
is a single grid layout manager.
- You would need 4 panels. One for each of the components then another
to place them in. Then you would place the outer most into a frame. A
single layout manager would work for this layout.
- The minimum number of layout managers is 3. One for every box.
- 3 box layouts and one border layout.
- One, by using the grid bag, you can state each component's relation
to on another.
- You only need one layout manager with can through variables be used
to do all 3 components.
- A single layout manager can be used with logic to add a new component
to the (x, y) coordinates of the preceding button's lower right corner.
- One layout manager could be used to get the design above.
- The number of layout needed are three. One for each box.