If you don't follow directions, your tests will fail and so will you.
Output rectangles one per line with the format x1 y1
x
x2 y2.
THIS SI FINAL DISPLAY OF AN ARRAY {[ 1, 1 ], [ 3, 3 ]} Level is : 0 Position is : 0 {[ 2, 2 ], [ 4, 4 ]} Level is : 1 Position is : 0
(cerr)
.
.cc
files.
#include "my-list.cc"
The road to wisdom?
Well it's plain and simple to express:
err and err and err again
but less and less and less.---- Piet Hein
Date: 14 Dec 2001 13:41:19 -0500 From: "R. Clayton" <rclayton@monmouth.edu> To: s0------@monmouth.edu Subject: Re: assignment 7 Since these are the final days of the semester, every deadline seems to come together at once. Could we have an extension for the final assignment for CS-509. Sorry, no deadline extensions.
Date: 29 Oct 2001 11:29:37 -0500 From: "R. Clayton" <rclayton@monmouth.edu> To: s0------@monmouth.edu Subject: Assignment deadline. I've had a report, a project, a mid-term test and your assignment due this week. Can I get an extension on the assignment? No, sorry - no extensions.
void eat_white() { while (cin && isspace(cin.peek())) cin.ignore(); } void f() { while(cin && (cin.peek() != EOF)) { cin >> s; eat_white(); } }
char *temp = new char[5]; strcpy(temp,"<FONT"); char *temp2 = new char[5];
bool readInst(List *L, char *&inst, int noInst) { char * line = new char[80]; inst = new char[80]; strcpy(inst, "\0"); line = L->getNext(); if ( line == NULL ) { inst = NULL; return false; } // blah blah blah }
main()
is not freeing storage.
// main function int main() { count = 0; // make counter to zero // Break the loop if temp_sum >= sum_of_vec while (temp_sum < sum_of_vec) {
// Loop while the temporary sum is less than // the vector sum. while (temp_sum < sum_of_vec) {
or just
while (temp_sum < sum_of_vec) {
// Represent expressions as binary trees.
// Insert the constant value n into the tree.
void main() { LList list; cout << "Please enter a sequence of sets of " << "algebraic eq. (ctrl+d) to end" << endl; int setCount = readInput(list); printResults(list, setCount); }
or
system()
.
system()
will be broken for testing.
A[-1]
is never correct.
A[4294967295]
.
This page last modified on 21 February 2002.