Command-line arguments again.

From: R. Clayton <rclayton_at_monmouth.edu>
Date: Tue, 27 Feb 2007 12:27:19 -0500

So far, I can't seem to get the simplest version of this program to work.

  That's because you're knocking on the wrong door. Programs access
  command-line arguments through the main() parameters argc and argv:

    int main(int argc, char * argv[]) {
      for (int i = 1; i < argc; i++)
        std::cout << argv[i] << "\n";
      }

  What C programming book are you using? Doesn't it explain this? If it
  doesn't you need to get a better book. Deitel and Deitel (third edition)
  explains it in Section 10.4, Command-Line Arguments.
Received on Tue Feb 27 2007 - 12:27:28 EST

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